Reverse of the given number using recursion in Java

public int reverse(int num) {
    if (num < 10) {
         return num;
    } else {

          int rev=num%10 * (int) Math.pow(10, (int) Math.log10(num));
          return  rev+ reverse(num / 10);

    }
}

      ------ OR --------

public int reverse(int num) {

   retrun (num < 10)? num:num%10 * (int) Math.pow(10, (int) Math.log10(num))

           +reverse(num / 10);

   }
}